Important
Self-managed SingleStore will soon transition from version 9.1 RC to version 10. This new semantic versioning scheme will provide SingleStore with finer control over engine and feature releases that were not possible with the current versioning scheme.
In the interim, SingleStore 9.1 RC can be used to preview, evaluate, and provide feedback on the new and upcoming features in SingleStore 10 prior to its general availability. Ahead of this transition, SingleStore 9.0 is recommended for production workloads, which can later be upgraded to SingleStore 10.
DATE_ SUB
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The DATE_ function subtracts the given interval of time to a date or datetime object.
Syntax
DATE_SUB (dateobj, INTERVAL expr unit)
SUBDATE (dateobj, INTERVAL expr unit)
SUBDATE (dateobj, days)Arguments
-
dateobj: a valid date, datetime, or parsable date string
-
expr: the number of units to add if unit is a simple type, or a string representation of the units to add if unit is a complex type.
Can be negative. -
days: number of days to subtract.
Can be negative.
See DATE_
Return Type
Date or datetime object.
Remarks
-
In
DATE_andSUB() SUBDATE()functions,MOD(.and. . ) a MOD bexpressions inINTERVALexpr unitsyntax are not supported without parentheses due to parser limitations.Use the modulo operator ( %), or wrap theMODexpression in parentheses.-- SupportedSELECT DATE_SUB('2020-01-01', INTERVAL 100 % 3 DAY);SELECT DATE_SUB('2020-01-01', INTERVAL (MOD(100, 3)) DAY);SELECT DATE_SUB('2020-01-01', INTERVAL (100 MOD 3) DAY);-- Not supportedSELECT DATE_SUB('2020-01-01', INTERVAL MOD(100, 3) DAY);SELECT DATE_SUB('2020-01-01', INTERVAL 100 MOD 3 DAY);
Examples
SELECT DATE_SUB('2010-04-02', INTERVAL 1 WEEK);
+-----------------------------------------+
| DATE_SUB("2010-04-02", INTERVAL 1 WEEK) |
+-----------------------------------------+
| 2010-03-26 |
+-----------------------------------------+Last modified: